# Ratio and Proportion Previous Year Questions asked in SSC CGL Mains(2018)

#### Ratio and Proportion is important topic in SSC CGL exam. SSC aspirants can expect 5 questions in each shift from this topic in Mains exam. Previous year Ratio and Proportion questions help you in your preparations. Total 15 Ratio and Proportion questions asked in SSC CGL Mains 2018 exam. Practice these questions over and over and Improve your efficiency.

**Ques.1.** Two numbers are in the ratio 3:5. If 13 is subtracted from each, the new number are in the ratio 10:21.If 15 is added to each of the original numbers, then the ratio becomes:

Options

A) 5:7

B)23:33

C) 4:5

**D) 24:35**

**Solution.**

(3 : 5) —-1

(10 : 21) —2

Multiply equation 1 by 11 and Multiply equation 2 by 2 so that their difference between numbers become equal

33 : 55

20 : 42

33-20= 13 and 55-42= 13

13= 13

Original ratio=33 : 55

New ratio after adding 15 = 48 : 70 which is equal to 24:35 Ans.

**Ques.2.** a, b and c Are three fractions such that a<b<c. If c is divided by a, the result is 9/2, which exceeds b by 23/6. The sum of a, b and c is 19/12. What is the value of(2a + b – c)?

Options

A) 1/2

B) 1/3

C) 1/12

D) 1/4

**Solution.** Given, c/a = 9/2 = c=9a/2

9/2-b=23/6,

so value of b=2/3

a+b+c= 19/12

Now, a+2/3 + c = 19/12

a+c= 11/12

a +9a/2 = 11/12

11a/2 =11/12

a= 1/6

c=3/4( after putting the value of a)

2a+b-c=2×1/6 + 2/3 -3/4

= 1/4 Ans

**Ques.3.** What is the ratio of the third proportional between 0.4 and 0.8 to the mean proportional between 13.5 and 0.24?

Options

A) 5 :4

B) 7:8

**C) 8:9**

D) 9:10

**Solutions.**

Third proportion = (0.8) ^2/0.4

Mean. Proportion= √13.5×0.24

Ratio =0.8×0.8/0.4×1.8 =16/18 = 8:9 Ans.

**Ques.4.** Two third of the number of employees of a company are males and the rest are females. If 3/8 of the male employees and 2/5 of the female employees Are temporary employees and the total number of permanent employees is 740, then 7/15 of the total number of employees exceeds the number of temporary female employees by:

Options

A) 400

B) 340

C) 308

D) 320

**Solutions.**

Let Total Number of Employees = 3

Male = 2

Temporary Male = 2×3/8 = 3/4

Permanent Male = 2×5/8 = 5/4

Female = 1

Temporary female =2/5

Permanent Female = 3/5

7/15 of total employees= 3×7/15 = 21/15

Difference of 7/15 of total employees and Number of Temporary female employees = 21/15 – 2/5 = 1

740× 1)/(5/3 + 3/5) = 400 Ans.

**Ques.5.** Three fractions, x, y,and z are such that x>y>z. when the smallest of them is divided by the greatest, the results is 9/16, which exceeds y by 0.0625. if x+y+z = 1 13/24, then the value of x+z is:

Options

A) 7/8

B) 1

**C) 25/24**

D) 7/6

Solutions.Given, z/x = 9/16 = z=9x/16

9/16-b=0.0625,

so value of y=1/2

x+y+z= 37/24

Now, x+1/2 + z = 37/24

x+z= 25/24

**Ques.5**. A sum of ₹ x is divided among A, B and C such that the ratio of the shares of A and B is 6:7 and that of B and C is 3:2. if the difference between the shares of A and C is ₹ 540, then the value of x is:

Options

A) 7425

B) 7020

**C) 7155**

D) 7290

**Solution.** A:B= 6:7 and B:C =3:2

after merging ratio

A(18) :(B) 21: (C) 14

difference between A and C is ₹540

and in ratio difference is 4

so, 4u=540

so value of x is = (540× 53) /4 = 7155 Ans.(here 53 is total of ratio)

**Ques.6.**The ratio of the volumes of two cylinder is X:Y and the ratio of their diameters is a:b.What is the ratio of their height?

Options

A) xb:ya

B) xa:yb

C) xb^2 :ya^2√

D) xa^2 :ya^2

**Solution.** V=πr^2h

X/Y =(π×a^2/2×h1) /π×b^2/2×h2)

=>h1/h2=xb^2/ya^2

**Ques. 7**.In a school, 4/9 of the number of students are girls and the rest are boys, 3/5 of the number of boys are below 12 years of age and 5/12 of the number of girls are 12 years or above 12 years of age. If the number of students below 12 years of age is 480,then 5/18 of the total number of students in the school will be equal to:

Options

A) 270

B) 315

**C) 225**

D) 240

**Solution**.Let total student=900

Boys = 500

Boys above 12 years=(3×500)/5=300

Boys below 12 years=(2×500)/5 =200

Girls= 400

Girls above 12 years = (7×400) /12

so. 1600/3 =480

(5×900)/18 =(480×3×250)/1600 =225 Ans

**Ques.8.** Let a, b and c be the fractions such that a<b<c. If c is divided by a, the results is 5/2, which exceeds b by 7/4, a+b+c = 1 11/12 then (c-a) will be equal to:

Option

A) 1/3

B) 2/3

C) 1/6

**D) 1/2**

**Solution**.Given, c/a = 5/2 = c=5a/2

5/2-b=3/4,

so value of b=3/4

a+b+c= 23/12

Now, a+3/4 + c = 23/12

a+c= 7/6

a +5a/2 = 7/6

7a/2 =7/6

a= 1/3

c=5/6( after putting the value of a)

c-a=5/6-1/3

= 1/2 Ans

**Ques.9.** The ratio of the income of A to that of B is 5:7. A and B save ₹4000 and ₹5000 respectively. If the expenditure of A is equal to 66 2/3% of the expenditure of B, then the total income of A and B is:

Options

A) ₹25200

**B) ₹24000**

C) ₹26400

D) ₹28800

**Solution.**Let A’s income =5x

A’s expenditure = 2y

B’s income = 7x

B’s expenditure=3y

Given

5x-2y =4000

7x-3y=5000

= x=2000 y=3000

Total income of A and B = 12x =24000 Ans

**Ques.10**.When x is added each of 2,3,30 and 35 then the numbers obtained in this order, are in proportion. What is the mean proportional between (x+7) and (x-2)?

Options

A)7

B) 4

**C) 6**

D) 5

**Solution.**

2+x/3+x = 30+x/35+x

= x=5

so mean proportion =√12+3 =6 Ans.

**Ques.11.** One year ago, the ratio of the age (in years) of A to that of B was 4:3. The ratio of their respective ages, 3 years from now, will be 6:5.What will be the ratio of respective ages of A and B, 9 years from now?

Options

A) 7:6

B) 10:9

**C) 9:8**

D) 8:7

**Solution.**

A : B

4 : 3(1year ago)

((6-4=2) same as, (5-3=2) so,2u=4)

6 : 5(3 year ago)

Ratio of age after 9 year.

A:B =(9+9) :(7:9)

=9:8 Ans.

**Ques.12.** In an office 5/8 of the total number of employees are males and the rest are females. 2/5 of the number of males are non- technical workers while 2/3 of the number of females are technical workers. what fractions of the total number of employees are technical workers?

Options.

A) 5/8

B) 2/5

C) 1/2

D) 3/8

**Solution.** Let total number of workers = 8

Male = 5

Female = 3

3+2/8 = 5/8 Ans.

**Ques.13** If (a+b) :(b+c) :(c+a) = 7:6:5

and a+b+c=27 then what will be the value of 1/a :1/b: 1/c?

Options

A) 3:6:4

B) 3:2:4

C) 4:3:6

D) 3:4:2

**Solution.** (a+b) :(b+c) :(c+a) = 7:6:5

(a+b+c) = 27

a=9

b=12

c=6

so, 1/a :1/b: 1/c = 1/9: 1/12: 1/6

=4:3:6 Ans.

**Ques.14.** A sum is divided among A, B, C and D such that the ratio of the shares of A and B is 2:3, That of B and C is 1:2 and that of C and D is 3:4.If the difference between the shares of A and D is ₹648, then the sum of the shares is:

Options

A) ₹2052

B) ₹2160

C) ₹2484

D) ₹1944

**Solution**

A:B = 2:3, B:C = 1:2 C:D = 3:4

merging all these ratios

A) 2 : (B) 3 : (C) 6 : (D) 8

Sum =648×19/6 = 108×19 =2052 Ans.

**Ques.15** The Ratio of the incomes of A and B last year was 4:3, respectively. The ratio of their individual incomes of the last year and present year are 3:4 and 5:6, respectively. If their total income for the present year is 8.04 lakh, then the income of B last year was:

Options

**A) ₹2.7 Lakh**

B) ₹3.6 Lakh

C) ₹2.4 Lakh

D) ₹2.8 Lakh

Solution. A_{l} = last year income of A

A_{p} = present year income of A

A_{l} : B_{l}

4 : 3

A_{p} : B_{p}

(4×4)/3 : (3×6)/5

16/3 : 18/5

40 : 27

B_{p} = 8.04×27/67

B_{l} : B_{p}

5 : 6

B_{l} = (8.04×27×5)/67×6

=2.7 lakh Ans.

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