Profit and Loss Previous Year Questions asked in SSC CGL Mains(2018)

Profit and Loss is important topic in SSC CGL exam. SSC aspirants can expect 3,4 questions in each shift from this topic in Mains exam.Previous year Profit and Loss questions help you in your preparations. Total 17 Profit and loss questions asked in SSC CGL Mains 2018 exam.Practice these questions over and over and Improve your efficiency.

(Note- Options Marked in Bold is correct ans.)

Ques.1. 35% of goods were sold at a profit of 65%, while the remaining were sold at x% loss if the overall loss is 12%, then what is the value of x?( correct to one decimal place)
Options A) 51.8 B)50.6 C) 53.5 D) 52.4

Solutions.Let total goods = 100 given., 35-65% profit 65-x % loss
According to question, 35×65/100 – 65× x/100 = 100×12/100
2275-65x=-1200
3475 =65x
x=53.46%
x= 53.5% ans.

Ques. 2. An article is sold at a profit of 14%. Had it been sold for ₹121 less, a loss of 8% would have been incurred. if the same article would have been sold for ₹ 536.25 then the profit/loss percent would have been:
Options A)Profit 5% B)loss 5% C) loss 2.5% D)profit 2.5%

Solution. CP -100 SP-114
difference of selling price =114-92= 22, so,
121×100/22 =550=CP
SP=536.25
loss% = 13.75×100/550 = 2.5% ans.

Ques.3. A shopkeeper allows 18% discount on the marked price of an article and still makes a profit of 23%. If he gains ₹ 18.40 on the sale of the article, then what is the marked price of the article?
Options A) ₹140 B) ₹125 C) ₹ 120 D) 146

Solution. SP = 82 MP = 100
Profit = 23 Profit in ₹ = 18.40 so, MP= 18.40×123×100/82×23
MP= 120 ANS.

Ques.4. A person buys 80kg of rice and sells it at a profit of as much money as he paid for 30 kg. His profit per cent is:
Options A) 27 3/11 B) 35 C) 40 D) 37 1/2

Solution. 80(SP- CP) = 30 CP
8 SP= 11 CP
CP/SP = 8/11
Profit% = 3×100/8= 75/2= 37 1/2% ans.

Ques.5.The marked price of an article is ₹1500. If two successive discounts, each of X% on the marked price is equal to single discount of ₹ 587.4 , then what will be the selling Price of the article if a single discount of X% is given on the marked price?
Options A) ₹ 1025 B) ₹ 1155 C) ₹ 1170 D) ₹ 1200

Solution.

(MRP)1500 (SP)1500-289.4( for two discounts)
2500(MP) 1521(SP)
(50)² (39)² (for one discount)
50 39
11×100/50 = 22%
SP= 1500 × 78/100 = 1170 ans.

Ques.6. An article is sold at the certain price. If it is sold at 80% of this price, then there will be a loss of 10% what is the percentage profit when the article is sold at the original selling price?
Options A) 15 1/2 B) 12 1/2 C) 15 D) 12

Solution.

CP(800/9) (SP)100
80×100/90 80
New C. P = 80×100/90( as loss in 10%)
SP =100
Profit = 100 – 80×100/90 = 100/9
Profit% = (100/9)×100/(800/9) = 12 1/2% ans.

Ques.7. By selling price two articles for ₹ 800, a person gains the cost price of three articles. The Profit percent is:
Options A) 125 B) 140 C) 120 D) 150
Solution: According to question
800- 2CP = 3CP
5CP = 800 CP/SP=160/400
As there are two articles Net CP 160×2 = 320
Net SP 400×2 =800
Profit% = 480×100/320 =150℅ ans.

Ques.8. Sujata marks an article 36% above the cost price and allows ba 40% discount on the marked price. The loss percentage is?
Options A) 15 B) 16.8 C) 18.4 D) 4

Solutions. (CP)100 (SP)136×60/100 (MP)136
100 81.6 136
loss% = 100-81.6
loss% = 18.4% ans.

Ques.9. A person sells an article at 16% below its cost price Had he sold it for ₹ 33 more, he would have gained 14%. To gain 25% he should sell the article for?
Options A) ₹128 B) ₹137.5 C) ₹135 D) ₹ 130.5

Solution. CP -100 SP = 84(16% below)——->114(14%above from CP)———>125(25% above from CP)
= 33×125/30 = 137.5 ans

Ques.10. A person marks his goods x% above the cost price and allows a discount of 30% on the marked price. If his profit is 5%, then the value of x will be?
Options A) 50 B) 60 C) 45 D) 35

Solution. MP/CP = 100+P/100-D
MP/CP= 105/70
X% = 35×100/70 = 50 ans

Ques.11. A shopkeeper bought 120 quintals of wheat 20% of it was sold at 25% loss. At what percent gain should be sell the rest to gain 25% on the whole transaction?
Options A) 36 1/2 B) 40 C) 37 1/2 D) 35

Solution.
-25% +x%
+25
1 : 4
x=125+25/4 = 37 1/2% ans.

Ques.12. Anu sold an article for ₹ 480 at some point. Had she sold it for ₹ 400, then there would have been a loss equal to one- third of the initial profit. what was the cost price of the article?
Options A) ₹450 B) ₹430 C) ₹425 D) ₹420

Solution. 400—–loss=x—–C.P—–profit=3x——480

=4x=80 => x=20 So, CP= ₹420ans.

Ques.13.A shopkeeper allows 28℅ discount on the marked price of an article and still makes a profit of 20%. If the gains 30.80 on the sale of one article, then what will be the cost price of the Article?
Options A) ₹164 B) ₹145 C) ₹ 160 D) ₹154

Solution
let CP= 100
Profit% = 20%
Profit in ₹ = 30.80
20%=30.80
100= 154
CP = 154 ans.

Ques.14. Radha marks her goods 25% above the cost price. She sells 35% of goods at the marked price, 40% at 15%, discount and the remaining at 20% discount. What is her overall percentage gain?
Options A) 11.25 B) 10 C) 11.75 D) 12.75

Solution. Let CP = 100
SP = 125×35/100 + 125 ×40/100×85/100+ 125×25/100×80/100 = 445/4
Profit% = 45/4% = 11.25% ans.

Ques.15. When article is sold for ₹ 355, there is a loss of 29%, To gain 21%, it should be sold for ₹:
Options A) 629.20 B) 580.8 C) 605 D) 635

Solution. According to Question
71% = 355
=121% = 355×121/71= 605 ans.

Ques.16 An article is sold at a certain price. If it is sold at 33 1/3 % of this price, there is a loss of 33 1/3 % . What is the percentage profit when it is sold at 60% of the original selling price?
Options A) 20 B) 30 C) 33 1/3 D) 17 1/3
Solution.
Let CP = 3x
New SP = 2x

Original S.P=2X×3=6X =60% of original S.P= 6X×60%= 3.6x

% profit= .6x/3x% =20% ans.
Ques.17. when the price of an item was reduced by 25%, then its sale was increased by X%. If there is an increase of 20% in the receipt of the revenue, then the Value of x will be:
Options A) 50 B) 60 C) 45 D) 75

Solution.

Price= 4(initial) 3(final)

Sale= 25 40

Revenue= 100 120

% increase in sale = 15/25% = 60% ans.

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Percentage Previous Year Questions asked in SSC CGL Mains(2018) Exam